Attack of The Crazy People
- Thread starter Blue Link
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I saw an episode of Bizarre Foods on the Travel Channel and they showed some bulls getting castrated. It's not as funny as it sounds. >.<
You're all depraved. First, it's beastiality porn, and now it's bulls getting their balls cut off.
Don't you have anything better to do?
Don't you have anything better to do?
You're all sad.
No. It was hard to watch. 
Don't make him bust out his FUCKING STAFF! 
dun dun dunnn
dun dun dunnn
Then I shall twist your brain with...non-Euclidean geometry.
And that's Dr. Gauss.
And that's Dr. Gauss.
It's great fun...
I confuse less easily than you, Ivan.
In that case, Dr. Gauss, I shall tie your limbs to a horse, stretch your body out, oil up a nearly sharpened stake and slowly impale you, making certain that every single moment is as painful as possible...
...that, or keep sending you nOOdz of men and women, not telling which is which until you open PM and find out. That's torture...
In that case, Dr. Gauss, I shall tie your limbs to a horse, stretch your body out, oil up a nearly sharpened stake and slowly impale you, making certain that every single moment is as painful as possible...
...that, or keep sending you nOOdz of men and women, not telling which is which until you open PM and find out. That's torture...
In that case, I shall...
1. If a number a divides the difference of the numbers b and c, b and c are said to be congruent relative to a; if not, b and c are noncongruent. The number a is called the modulus. If the numbers b and c are congruent, each of them is called a residue of the other. If they are noncongruent they are called nonresidues.
The numbers involved must be positive or negative integers, not fractions. For example, -9 and +16 are congruent relative to 5; -7 is a residue of +15 relative to 11, but a nonresidue relative to 3. Since every number divides zero, it follows that we can regard any number as congruent to itself relative to any modulus.
2. Given a, all its residues modulo m are contained in the formula a + km where k is an arbitrary integer. The easier propositions that we state below follow at once from this, but with equal ease they can be proved directly.
Henceforth we shall designate congruence by the symbol m, joining to it in parentheses the modulus when it is necessary to do so; e.g, -7 = 15 mod 11, -16 = 9 mod 5.
3. THEOREM. Let m successive integers a, a + 1, a + 2, ... a + m - 1 and another integer A be given; then one, and only one, of these integers will be congruent to A relative to m.
If (a-A)/m is an integer then a = A; if it is a fraction, let k be the next larger integer (or if it is negative, the next smaller integer not regarding sign). A + km will fall between a and a + m and will be the desired number. From the Disquisitiones Arithmeticae.
And by the way, did you know there are triangles whose angles don't sum to 180?
If you haven't had enough, then I shall prove Menelaus' theorem, then prove Pappus' theorem, then Brianchon's.
Slowly, but surely...
1. If a number a divides the difference of the numbers b and c, b and c are said to be congruent relative to a; if not, b and c are noncongruent. The number a is called the modulus. If the numbers b and c are congruent, each of them is called a residue of the other. If they are noncongruent they are called nonresidues.
The numbers involved must be positive or negative integers, not fractions. For example, -9 and +16 are congruent relative to 5; -7 is a residue of +15 relative to 11, but a nonresidue relative to 3. Since every number divides zero, it follows that we can regard any number as congruent to itself relative to any modulus.
2. Given a, all its residues modulo m are contained in the formula a + km where k is an arbitrary integer. The easier propositions that we state below follow at once from this, but with equal ease they can be proved directly.
Henceforth we shall designate congruence by the symbol m, joining to it in parentheses the modulus when it is necessary to do so; e.g, -7 = 15 mod 11, -16 = 9 mod 5.
3. THEOREM. Let m successive integers a, a + 1, a + 2, ... a + m - 1 and another integer A be given; then one, and only one, of these integers will be congruent to A relative to m.
If (a-A)/m is an integer then a = A; if it is a fraction, let k be the next larger integer (or if it is negative, the next smaller integer not regarding sign). A + km will fall between a and a + m and will be the desired number. From the Disquisitiones Arithmeticae.
And by the way, did you know there are triangles whose angles don't sum to 180?
If you haven't had enough, then I shall prove Menelaus' theorem, then prove Pappus' theorem, then Brianchon's.
Slowly, but surely...
THROW IN THE TOWEL VLAD, LEST YOU BECOME SO CONFUSED YOUR BRAIN IMPLODES
You do realize that Ivan died from internal putrification. Which means that he died from being constipated too long.
*Prods Vlad's brain bits with knobbed stick*